Wifi Access can anyone help

blinko

Hi all

I need help here

at home I have 2 computers and a wifi network thing

the problem i have is when both computers are connected to the internet at the same time only one net connection will work

how can we configure the wifi access so we can both use the internet at the same time ?

there are only 2 computers connected to this wifi network

we are using windows vista and windwos XP and we both have firewalls activated

thanks

Browntoa

should both work at the same time

who supplies your broadband ??

I'll move this to techie , think you will get better hepl ther

blinko

thanks buddy its talk talk, i thought 2 computers could use the same net connection at the same time ??

Can they both work separately then, if yes that seems odd because a router should allow both to work same time, unless bother laptops are set for using same IP address rather then the default dynamic IP

so i need to set the IP address to dynamic ?

how would i do that ta

blinko

we have our on one that we use

safesound

Please confirm you have two computers connected (wirelessly?) to a router (not a modem) and each computer has its own (ie, different) IP address.
Can you see both computers from the router config page?
What router are you using?

JasX

would be useful if you could find a make+model number on the back of your modem/router too

blinko

i have 2 seperate comps both connected wirelessly to a

im prettys ure they both have different IP address one is using XP other vista

its a echolife 520 modem

debitcardmayhem

On each pc click on the "start" button then run and enter cmd or press the windows key + r on the keyboard and enter cmd
In the window that opens up enter ipconfig and look for the IP address for each pc post them on here and also the default gateway address too

blinko

adsl mode is set to mulitmode

blinko

PC 1

deafult = 192.168.1.1
ipv4 = 192.168.1.4
subnet mask = 255.255.255.0
link local ipv4 address = fe80::d157.6876.9070.be5d%24

blinko

PC2

deafult = 192.168.1.1
Ip = 198.168.1.2