We'd like to remind Forumites to please avoid political debate on the Forum... Read More »
This is to keep it a safe and useful space for MoneySaving discussions. Threads that are - or become - political in nature may be removed in line with the Forum’s rules. Thank you for your understanding.
📨 Have you signed up to the Forum's new Email Digest yet? Get a selection of trending threads sent straight to your inbox daily, weekly or monthly!
I notice you can’t add a second card to Apple Pay so I would have to use Chase.
I am not sure what you mean. I have 14 cards in my ApplePay, and am sure I could add more if I had any more cards.
There is a limit to the number of payment (debit/credit) cards you can register with Apple Pay. I believe the maximum number is 8 cards for iPhone models 7 and below, and 16 cards for later models. Transit cards have a separate limit (which was 4 before iOS 16). Cards/passes that don't utilise the Secure Element (such as loyalty schemes) are not subject to either limit, though there could be a total upper limit of 64 cards.
You might be right that there is an upper limit - not that this would appear to be an issue for the OP who barely has 2 cards they want to add.
By the sounds of those Reddit posts, it's not even an issue if I really wanted to add loads more to my current 14 cards on my 15 Pro Max, and on my Apple Watch.
It appears to be variable as of iOS 17 based solely on Secure Element capacity, so you won't know your own soft limit until you hit it (if ever) and then your iPhone will report on its proportional usage.
I know at least one iPhone 15 Pro Max user who wasn't able to add more than a 16th card payment card, but it must have been a coincidental case.
I did raise a complaint and was told wait the 30 days. It’s now been six weeks still can’t add the card. I am guessing I won’t be able to add this card again or my joint account? I did set up a chase bank account so it’s fine other than I need to send all my wages over to Apple Pay. Anybody else had this issue with banks before?
