Physics / mechanics help pls

Anyone good at mechanics problem solving please?  It's a simple situation but I don't know the answer.  

Suppose you have a weight, say 100 kg for a round number, and it is suspended by two ropes.  Now if those ropes were vertical, the weight on each would be 50 kg.  But what happens if the ropes are fixed at an angle like say 30º to the vertical?  I would guess they see a higher weight loading?  But how much more, if so?  
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  • Mickey666
    Mickey666 Posts: 2,834 Forumite
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    Where would any extra weight come from?

  • coffeehound
    coffeehound Posts: 5,741 Forumite
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    edited 17 February 2021 at 11:28AM
    I was thinking of the edge case where if you tried to pull on the ropes to bring the load towards horizontal, you need to use increasing force.  So therefore the ropes must see a higher weight as you increase the angle?  
  • The load on two the two ropes would still be 50 kg each, based on them both taking equal load, or split to a combined total of 100kg (eg 70/30, 60/40). A 100kg weight at rest will exert 100kg (980 Newtons) of downward pressure (in a simplified example, real world there are slight variables), other factors come into play in an engineering situation, but the mass does not change. 
  • pbartlett
    pbartlett Posts: 1,397 Forumite
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    Are you asking about the tension on the ropes? This will decrease as the weight moves around the angles until when the ropes are horizontal the tension in the ropes is zero
  • rdr
    rdr Posts: 409 Forumite
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    If the two ropes are are the same length and so the weight is evenly supported, the tension in each rope will be = (1/2)(Mg/cosϴ) N, where M= the hanging mass, g=  acceleration due to gravity (=9.8 m/s²), ϴ = between the rope and vertical.
    for a 100kg mass and a 30° angle the tension in each rope will be 566 N. This is equivalent to the force produced by suspending a mass of 57.7 kg.
  • grumpycrab
    grumpycrab Posts: 5,012 Forumite
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    pbartlett said:
    when the ropes are horizontal the tension in the ropes is zero
    what's keeping the weight up at this point?
    If you put your general location in your Profile, somebody here may be able to come and help you.
  • Chino
    Chino Posts: 2,031 Forumite
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    rdr said:
    This is equivalent to the force produced by suspending a mass of 57.7 kg.
    Hadn't seen your post but I'd calculated the tension in each angled rope as being 2/SQRT(3) times greater than when the ropes are vertical, which agrees.
  • coffeehound
    coffeehound Posts: 5,741 Forumite
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    edited 17 February 2021 at 3:57PM
    Thanks all, appreciate your quick responses.  The 'ropes' in this project are a chain of seven different components which I originally spec'd for the basic slung weight, before having a 'hold on!' moment this morning.  Will need to measure the actual angle with everything assembled and do the calcs to check that each item can cope with the increased equivalent weight.  ~15% uplift for a 30º angle is pretty significant.
  • pbartlett
    pbartlett Posts: 1,397 Forumite
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    pbartlett said:
    when the ropes are horizontal the tension in the ropes is zero
    what's keeping the weight up at this point?
    Not the rope
  • pbartlett
    pbartlett Posts: 1,397 Forumite
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    edited 17 February 2021 at 2:51PM
    The ropes at 30deg will see a lower tension and so can be less spec'd - this is because some of the load will be taken by the additional force you need to stop the mass simply swinging down to vertical again. As rdr says, the tension in the ropes decreases as a function of cos(theta), which is 1 when the ropes are vertical (hence then support the full 100kg), to zero when they are horizontal - in that case the rope could be made of cotton as there is no tension in it.
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