Confused

Just_landed

I’m confused I want to replace the batteries in a cordless drill power pack which is 14.4 v. there are 12 of 1.2 volt x 1500mAh Ni-Cd batteries in the pack. I Know I can buy the right batteries from eBay but they are quit dear to other options around. I have been told I can put in 1.2 Amp or 2.0 Amp. Would I divide say 2 Amp by 12 to get the amperage of each battery required ? would someone explain how to arrive at what I want.

Thank you :think:

John_Gray

Since there are 12 x 1.2 V batteries with a total voltage of 14.4 V, then the batteries must be in series (lots more electronics, otherwise). So the required current will flow through ALL the batteries.

I would replace the batteries with those of the same current rating...!

Just_landed

thanks for the reply, looking like I will have to stick to 1500mAh. Been mooching about on internet and what I've found is 1500mAh is = to 1.5 Amps but can't seem to find any much cheaper. So as you say electronics inside, I will stick with equal ones.
thanks

John_Gray

1500 mAh is not a current but a current for a period of time. For example, it means that the battery would/could/should give 1500 mA = 1.5 A for an hour, or 750 mA = 0.75A for 2 hours, and so on (other things being equal, which they aren't!).

mAh is a measure of the capacity of the battery.

For laptop batteries, the higher-capacity ones will keep the laptop going longer...

Just_landed

John_Gray wrote: »

1500 mAh is not a current but a current for a period of time. For example, it means that the battery would/could/should give 1500 mA = 1.5 A for an hour, or 750 mA = 0.75A for 2 hours, and so on (other things being equal, which they aren't!).

mAh is a measure of the capacity of the battery.

For laptop batteries, the higher-capacity ones will keep the laptop going longer...

Magic, what a great explanation, thank you.