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Heat Used - Physics Question

Could anyone help with a question relating to:

The amount of heat required to raise a building 500 cubic meters by 1 degree C (assuming no heat loss).

I have used the internet but do not believe the answer. The calculation is:

Specific Heat x Density x Volume x Temp Rise
1.00 x 1275 x 500 x 1 = 637000 Kj

When I convert to watts I have an answer of 176 watts, which I do not believe! 637000/3600 = 176 watts

Can anyone validate for me please.

Robert
«13

Comments

  • 637000 kJ is 176 kWh, not Wh.
  • Smiley_Dan wrote: »
    637000 kJ is 176 kWh, not Wh.

    Thank you for the reply, but that now seems way to high. The 500 cubic meter building is a typical mid sized house. Am I missing something that you could help on?
  • firefox1956
    firefox1956 Posts: 1,548 Forumite
    Well I no nowt about fisics but..........
    500 cubic metres sounds a bl**dy big house !!
    Are you sure it is not 50 cubic metres ??
  • It's 10 meters X 10 meters x 5 meters high over 2 floors. Therefore 500 meters cubed.
  • Nada666
    Nada666 Posts: 5,004 Forumite
    edited 7 January 2015 at 11:24AM
    Well I no nowt about fisics but..........
    500 cubic metres sounds a bl**dy big house !!
    Are you sure it is not 50 cubic metres ??
    I think you're confusing cubic metres with square metres.

    10 x 10 x 5 is not large (take a couple off the height, though)

    70 x 70 is!

    (crossed posts!)
  • Robwiz
    Robwiz Posts: 364 Forumite
    A mid sized house would have a floor area of around 90 m^2 over two floors so the volume would be more like 225 m^3.
  • Nada666
    Nada666 Posts: 5,004 Forumite
    Robwiz wrote: »
    A mid sized house would have a floor area of around 90 m^2 over two floors so the volume would be more like 225 m^3.
    That is very small. Statistically for our hideous shoeboxes nowadays it may well be 'mid' but I can't imagine anyone living in one actually calling it 'mid-sized'. That's barely enough for one room and a hallway wide and another narrow room deep.
  • I still think that my 500m3 is reasonable, but may not be mid sized.

    It's the KW used on 500m3 that I need some input on.

    Thanks
  • btr30
    btr30 Posts: 145 Forumite
    Part of the Furniture 100 Posts Combo Breaker
    I still think that my 500m3 is reasonable, but may not be mid sized.

    It's the KW used on 500m3 that I need some input on.

    Thanks

    I think your calculations are OK, but you have missed the important factor of heat loss. Also if you were to raise the temperature from 10 to 20 DegC it would take 10 times the Energy i.e 1.76 kW in your example.
  • btr30 wrote: »
    I think your calculations are OK, but you have missed the important factor of heat loss. Also if you were to raise the temperature from 10 to 20 DegC it would take 10 times the Energy i.e 1.76 kW in your example.

    I didn't want to confuse this thread with the heat loss calculation, that's another matter. Just wanted to obtain some support on my method and result for the temperature rise calculation.
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