E: 08/10 win an ipad or other Krave goodies(FB)

Runnerduck

https://www.facebook.com/Krave/app_398411583551730

a. 1 x iPad 16GB with wifi.
b. 1 x supply of Krave cereal (crate of 8 boxes).
c. 1 x Krave branded hoody.
d. 1 x Krave branded cereal bowl.
e. 1 x white speakers.

Idol_Eyes

Prizes include Krave goodies and an iPad!

glamrochick

Guess this is luck of the draw

bigbloke45

This is one time you really DO need to be a rocket scientist! :rotfl:

tallenuk

You can use the equations of motion to get a rough idea of a upper limit.
I'd say looking at the blueprint the angle is about 38 degrees (Sin^-1 (2.5/4)). Therefore the vertical speed on launch is 0.625*26.82=16.76 m/s.
Vertical Velocity zero at end [it hits the ground] so 0=16.76 - 1/2 * 9.81 * t^2. [0=v+0.5at^2] Rearrange to solve for t = 2x1.85s. (1.85 seconds of flight)

Therefore it shouldn't travel further than (As this calculation doesn't take air resistance+ friction into account)
1.85*2* cos(38)*26.82=78m


Tho with air resistance I'd expect it to be half of this, at around 30m. 60mph is very slow! It's pretty much guesswork. I went for 12 m as trolleys are very unbalanced towards the rear with the rocket causing it to rotate and the cereal fall out.

bigbloke45

tallenuk wrote: »

You can use the equations of motion to get a rough idea of a upper limit.
I'd say looking at the blueprint the angle is about 38 degrees (Sin^-1 (2.5/4)). Therefore the vertical speed on launch is 0.625*26.82=16.76 m/s.
Vertical Velocity zero at end [it hits the ground] so 0=16.76 - 1/2 * 9.81 * t^2. [0=v+0.5at^2] Rearrange to solve for t = 1.85s. (1.85 seconds of flight)

Therefore it shouldn't travel further than (As this calculation doesn't take air resistance+ friction into account)
1.85* cos(38)*26.82=39 Meters


So it's gonna be less than 30M realistically, taking air resistance into account.

I told you so! :rotfl:

sofaloafz

tallenuk wrote: »

You can use the equations of motion to get a rough idea of a upper limit.
I'd say looking at the blueprint the angle is about 38 degrees (Sin^-1 (2.5/4)). Therefore the vertical speed on launch is 0.625*26.82=16.76 m/s.
Vertical Velocity zero at end [it hits the ground] so 0=16.76 - 1/2 * 9.81 * t^2. [0=v+0.5at^2] Rearrange to solve for t = 1.85s. (1.85 seconds of flight)

Therefore it shouldn't travel further than (As this calculation doesn't take air resistance+ friction into account)
1.85* cos(38)*26.82=39 Meters


So it's gonna be less than 30M realistically, taking air resistance into account.

Is that just for the trolley? Remember you can guess where the cereal will land. And it's rocket powered.

Gilla_2

Yuk. I hate white chocolate.